???????????????????????????????????????????????????? $\bullet$ (-x-1)^2-3x+3=0 <=> x^2+2x+1-3x+3=0 <=> x^2+(2x-3x)+(1+3)=0 <=> x^2-x+4=0 <=> x^2-2.x . 1/2+(1/2)^2-(1/2)^2+4=0 <=> (x-1/2)^2+15/4=0 <=> (x-1/2)^2=-15/4 => Vô lí vì (x-1/2)^2>=0 ∀x Vậy x ∈ ∅ Trả lời
1 bình luận về “Tìm x `(-x-1)^2 -3x+3=0`”