`3x + 13` $\vdots$ `x + 1` helppppppppp

1 bình luận về “`3x + 13` $\vdots$ `x + 1` helppppppppp”

1. Ta có :3x + 13 = 3x + 3 + 10 = 3(x + 1) + 10

   Để 3x + 13 \vdots x + 1 thì

   10 \vdots x + 1

   =>x + 1 \in Ư(10)

   => x + 1 \in {+-1,+-2,+-5,+-10}

   => x \in {-11,-6,-3,-2,0,1,4,9}

   Vậy x \in {-11,-6,-3,-2,0,1,4,9} thì 3x + 13 \vdots x + 1

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