2 ( x^2 + 3x – 5 ) – 2x^2 (x – 3)^2 – x^2 + 2 6x – 12y x^2 + 8x + 16 x^2 – 4 + 3xy + 6y

1 bình luận về “2 ( x^2 + 3x – 5 ) – 2x^2 (x – 3)^2 – x^2 + 2 6x – 12y x^2 + 8x + 16 x^2 – 4 + 3xy + 6y”

1. 2(x^2 + 3x – 5) – 2x^2

   = 2x^2 + 6x – 10 – 2x^2

   = (2x^2 – 2x^2) + 6x – 10

   = 6x – 10

   (x-3)^2 – x^2 + 2

   = x^2 – 6x + 9 – x^2 + 2

   = (x^2 – x^2) – 6x + (9 + 2)

   = -6x + 11

   6x – 12y

   = 6(x – 2y)

   x^2 + 8x + 16

   = x^2 + 2.4.x + 4^2

   = (x+4)^2

   x^2 – 4 + 3xy + 6y

   = (x^2-4) + (3xy + 6y)

   = (x+2)(x-2) + 3y(x + 2)

   = (x+2)(x-2+3y)

   #BlackStar

    

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