Trang chủ » Hỏi đáp » Môn Toán `(1).(x+4)/3=19/22` `(2).x+12/6=17/2+1/2` 17/05/2023 `(1).(x+4)/3=19/22` `(2).x+12/6=17/2+1/2`
(1) (x+4)/3=19/22 (x+4)xx22=19xx3 (x+4)xx22=57 x+4=57:22 x+4=57/22 x=57/22-4 x=57/22-88/22 x=57/22+(-88)/22 x=(-31)/22 Vậy x=(-31)/22 (2) x+12/6=17/2+1/2 x+2=17/2+1/2 x+2=9 x=9-2 x=7 Vậy x=7 \color{green}{\text{~Bachira~}} Trả lời
1) (x+4)/3=19/22 =>(x+4)xx22=3xx19 =>(x+4)xx22=57 =>x+4=57/22 =>x=57/22-4 =>x=(-31)/22 Vậy x=(-31)/22 (2) x+12/6=17/2+1/2 =>x+2=9 =>x=9-2 =>x=7 Vậy x=7 Trả lời
2 bình luận về “`(1).(x+4)/3=19/22` `(2).x+12/6=17/2+1/2`”