x+4/2019+x+ 3/2020=x+2/2021+x+ 1/2022

2 bình luận về “x+4/2019+x+ 3/2020=x+2/2021+x+ 1/2022”

1. Giải đáp + Lời giải và giải thích chi tiết:

             (x + 4)/2019 + (x + 3)/2020 = (x + 2)/2021 + (x + 1)/2022

     <=> (x + 4)/2019 + (x + 3)/2020 + 2 = (x + 2)/2021 + (x + 1)/2022 + 2

     <=> ((x + 4)/2019 + 1) + ((x + 3)/2020 + 1) = ((x + 2)/2021 + 1) + ((x + 1)/2022 + 1)

     <=> ((x + 4)/2019 + 2019/2019) + ((x + 3)/2020 + 2020/2020) = ((x + 2)/2021 + 2021/2021) + ((x + 1)/2022 + 2022/2022)

     <=> (x + 4 + 2019)/2019 + (x + 3 + 2020)/2020 = (x + 2 + 2021)/2021 + (x + 1 + 2022)/2022

     <=> (x + 2023)/2019 + (x + 2023)/2020 = (x + 2023)/2021 + (x + 2023)/2022

     <=> (x + 2023)/2019 + (x + 2023)/2020 – (x + 2023)/2021 – (x + 2023)/2022 = 0

     <=> (x + 2023)(1/2019 + 1/2020 – 1/2021 – 1/2022) = 0

     <=> x + 2023 = 0   ( Vì 1/2019 + 1/2020 – 1 /2021 – 1/2022 \ne 0)

     <=> x = -2023

             Vậy: x = -2023

   ~MioWiky~

   Trả lời
2. (x+4)/2019+(x+3)/2020=(x+2)/2021+(x+1)/2022

   <=> ((x+4)/2019+1)+((x+3)/2020+1)-((x+2)/2021+1)-((x+1)/2022+1)=0

   <=> (x+2023)/2019+(x+2023)/2020-(x+2023)/2021-(x+2023)/2022=0

   <=> (x+2023) . (1/2019+1/2020-1/2021-1/2022)=0

    Mà (1/2019+1/2020-1/2021-1/2022)\ne0

   <=> x+2023=0

   <=> x=-2023

   Vậy x=-2023

   $\color{red}{\text{@Hy~Hoctotnha}}$ 

   Trả lời