Giải pt: `x – (2x-2)/5 + (x+8)/6 = 7 + (x-1)/3`

2 bình luận về “Giải pt: `x – (2x-2)/5 + (x+8)/6 = 7 + (x-1)/3`”

1. $x-\dfrac{2x-2}{5}+$ $\dfrac{x+8}{6}=7+$ $\dfrac{x-1}{3}$

   <=>$\dfrac{30x}{30}-$ $\dfrac{6(2x-2)}{30}+$ $\dfrac{5(x+8)}{30}=$ $\dfrac{210}{30}+$ $\dfrac{10(x-1)}{30}$ 

   <=> 30x-12x+12+5x+40=210+10x-10

   <=> 23x+52=200+10x

   <=> 23x-10x=200-52

   <=> 13x=148

   <=> x=148/13

   Vậy tập No pt là S={148/13}

   ~~Hok tốt~~

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   Trả lời
2. x-(2x-2)/5+(x+8)/6=7+(x-1)/3

   <=>30x-6(2x-2)+5(x+8)=30.7+10(x-1)

   <=>30x-12x+12+5x+40=210+10x-10

   <=>30x-12x+12+5x+40-210-10x+10=0

   <=>13x-148=0

   <=>13x=148

   <=>x=148/13

   Vậy S={148/13}

   Trả lời