tìm `x`, biết`x/2019+(x+1)/2018+(x+2)/2017+(x+3)/2016=-4`

2 bình luận về “tìm `x`, biết`x/2019+(x+1)/2018+(x+2)/2017+(x+3)/2016=-4`”

1. x/2019+(x+1)/2018+(x+2)/2017+(x+3)/2016=-4

   => x/2019+(x+1)/2018+(x+2)/2017+(x+3)/2016+4=0

   => x/2019+1+(x+1)/2018+1+(x+2)/2017+1+(x+3)/2016+1=0

   => (x+2019)/2019+(x+2019)/2018+(x+2019)/2017+(x+2019)/2016=0

   => (x+2019)(1/2019+1/2018+1/2017+1/2016)=0

   Vì 1/2019+1/2018+1/2017+1/2016 >0

   Nên x+2019=0

   => x=-2019

   Vậy x=-2019

   Trả lời
2. x/2019 + (x+1)/2018 + (x+2)/2017 + (x+3)/2016 = -4

   <=> (x/2019 + 1) + ((x+1)/2018 + 1) + ((x+2)/2017 + 1) + ((x+3)/2016 + 1) = 0

   <=> (x+2019)/2019 + (x+2019)/2018 + (x+2019)/2017 + (x+2019)/2016 = 0

   <=> (x+2019) (1/2019+1/2018+1/2017+1/2016) = 0

   <=> x+2019=0

   <=> x=-2019

   Vậy x=-2019

   Trả lời