A=(1+ 1/2)x(1+1/3)x(1+1/4)x………x(1+1/2022)

2 bình luận về “A=(1+ 1/2)x(1+1/3)x(1+1/4)x………x(1+1/2022)”

1. A =( 1 + $\frac{1}{2}$ ) x (1 + $\frac{1}{3}$) x ( 1 + $\frac{1}{4)}$) x … x ( 1 + $\frac{1}{2022}$ )

   A =$\frac{3}{2}$ x $\frac{4}{3}$ x $\frac{5}{4}$ x … x $\frac{2023}{2022}$

   A = $\frac{3 x 4 x 5 x… x 2023}{2 x 3 x 4x…x2022}$  

   A = $\frac{2023}{2}$ 

   A = 1011,5

   Vì 1011,5 > 1000 nên A > 1000

   Vậy A > 1000

   @lethainhatduong111#hoidap247

   Trả lời
2. A= (1 + 1/2) ( 1 + 1/3) ( 1 + 1/4) … ( 1 + 1/2022)

   = 3/2 . 4/3 . 5/4 … 2023/2022

   = (3.4.5…2023)/(2.3.4…2022)

   =(2023)/(2) = 1011,5

   Mà 1011,5 > 1000

   => A > 1000.

    

   Trả lời