There are three numbers such that the second is four times the first, the third is 3 less than the first. The sum of the firs

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1. @ \text{Ché}

   Call the first number a.

   ⇒ The second number is : 4×a.
   ⇒ The third number is : 1/3×a.
   We have : a+1/3×a=27
       ⇒ a×(1+1/3)=27
       ⇒ a×4/3=27
       ⇒ a=27÷4/3
       ⇒ a=81/4
   The second number is : 4×81/4=81
   The third number is : 1/3×81/4=27/4.
   The average is : (81/4+81+27/4)÷3=36.
   Answer : Average : 36.

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