Trang chủ » Hỏi đáp » Môn Toán 1/31+1/32+1/33+…+1/60. CMR: A< 5 /6 26/10/2023 1/31+1/32+1/33+…+1/60. CMR: A< 5 /6
A=1/31+1/32+1/33+…+1/60 =(1/31+1/32+…+1/40)+(1/41+1/42+…+1/50)+(1/51+1/52+…+1/60) ( Mỗi phần trong ngoặc gồm 10 số hạng ) Nhận xét:+)1/31<1/30 1/32<1/30 … 1/40<1/30 =>1/31+1/32+…+1/40<1/30+1/30+…+1/30=1/30 .10=1/3 +)1/41<1/40 1/42<1/40 … 1/50<1/40 =>1/41+1/42+…+1/50<1/40+1/40+…+1/40=1/40 .10=1/4 +)1/51<1/50 1/52<1/50 … 1/60<1/50 =>1/51+1/52+…+1/60<1/50+1/50+…+1/50=1/50 .10=1/5 Từ đó suy ra A<1/3+1/4+1/5=47/60<50/60=5/6 Vậy A<5/6(Q.E.D) Trả lời
+)1/31<1/30