(2x-1)^2=4/9 ///////////////////////////////////////////////////

2 bình luận về “(2x-1)^2=4/9 ///////////////////////////////////////////////////”

1. (2x-1)^2 = 4/9

   => (2x-1)^2 = ( 2/3 )^2 hoặc ( 2x-1)^2 = (-2/3)^2

   => $\left[\begin{matrix} 2x-1=\dfrac{2}{3}\\ 2x-1=-\dfrac{2}{3}\end{matrix}\right.$

   => $\left[\begin{matrix} 2x=\dfrac{5}{3}\\ 2x=\dfrac{1}{3}\end{matrix}\right.$

   => $\left[\begin{matrix} x=\dfrac{5}{6}\\ x=\dfrac{1}{6}\end{matrix}\right.$

   Vậy x ∈ { 5/6 ; 1/6 }

   Trả lời
2. Giải đáp: x in {5/6;1/6}

   Lời giải và giải thích chi tiết:

   (2x-1)^2=4/9

   =>(2x-1)^2=(2/3)^2=(- 2/3)^2

   =>\(\left[ \begin{array}{l}2x-1=\dfrac{2}{3}\\2x-1=-\dfrac{2}{3}\end{array} \right.\) 

   =>\(\left[ \begin{array}{l}2x=\dfrac{2}{3}+1\\2x=-\dfrac{2}{3}+1\end{array} \right.\) 

   =>\(\left[ \begin{array}{l}2x=\dfrac{2}{3}+\dfrac{3}{3}\\2x=-\dfrac{2}{3}+\dfrac{3}{3}\end{array} \right.\) 

   =>\(\left[ \begin{array}{l}2x=\dfrac{5}{3}\\2x=\dfrac{1}{3}\end{array} \right.\) 

   =>\(\left[ \begin{array}{l}x=\dfrac{5}{3}.\dfrac{1}{2}\\x=\dfrac{1}{3}.\dfrac{1}{2}\end{array} \right.\) 

   =>\(\left[ \begin{array}{l}x=\dfrac{5}{6}\\x=\dfrac{1}{6}\end{array} \right.\) 

   $Vậy$ x in {5/6;1/6}

   Trả lời