a.159-(25-x)=43 b.(79-x)-43=-(17-52) c.-(-x+13-142)+18=55 d.x-15=-25 e.-x-(-33)=44 f.x+(-23)

2 bình luận về “a.159-(25-x)=43 b.(79-x)-43=-(17-52) c.-(-x+13-142)+18=55 d.x-15=-25 e.-x-(-33)=44 f.x+(-23)”

1. a) 159-(25-x)=43

   => 25-x=159-43

   => 25-x=116

   => x=25-116

   => x=-91.

   Vậy x=-91.

   b) (79-x)-43=-(17-52)

   => (79-x)-43=35

   => 79-x= 35+43

   => 79-x=78

   => x=1.

   Vậy x=1.

   c) -(-x+13-142)+18=55

   => x-13+142=55-18

   => x-13+142=37

   => x-13=37-142

   => x-13=-105

   => x= -105+13

   => x= -92.

   Vậy x=-92.

   d) x-15=-25

   => x= -25+15

   => x= -10.

   Vậy x=-10.

   e) -x-(-33)=44

   => -x+33=44

   => -x= 44-33

   => -x= 11

   => x= -11.

   Vậy x=-11.

   f) x+(-23)=(-100)+77

   => x-23= -23

   => x= -23+23

   => x= 0.

   Vậy x=0.

   g) x-(-50)=16

   => x+50=16

   => x= 16-50

   => x= -34.

   Vậy x=-34. 

   h) x+13=32-56

   => x+13= -24

   => x= -24-13

   => x= -37.

   Vậy x=-37.

   i) -15-x=(-14)-(-57)

   => -15-x=43

   => x= -15-43

   => x= -58.

   Vậy x= -58.

   j) |x-1|=5

   => \(\left[ \begin{array}{l}x-1=5\\x-1=-5\end{array} \right.\) 

   => \(\left[ \begin{array}{l}x=5+1\\x=-5+1\end{array} \right.\)

   => \(\left[ \begin{array}{l}x=6\\x=-4\end{array} \right.\)

   Vậy x ∈ {6;-4}

   Trả lời
2. Giải đáp + Lời giải và giải thích chi tiết:

   a.159-(25-x)=43

   25-x = 159 -43

   25 – x = 116

   x = 25-116

   x = -91

   ______________________

   b,(79-x)-43 = -(17-52)

   (79-x)-43 = 35

   79-x = 35 + 43

   79-x = 78

   x = 79-78

   x = 1

   _____________________________

   c, -(-x+13-142) + 18=55

   x+13-142 + 18=55

   x+13 -142 = 55-18

   x+13-142 = 37

   x+13 = 37 + 142

   x+13 = 179

   x = 179-13

   x =166

   __________________________

   d, x – 15 = -25

   x = -25 + 15

   x = -10

   _________________________

   e,-x-(-33) = 44

   -x + 33 = 44

   -x = 44-33

   -x = 11

   x = -11

   ____________________

   f, x + (-23) = (-100) + 77

   x + (-23) = -23

   x = -23 – (-23)

   x = 0

   ___________________________

   g,x-(-50) = 16

   x + 50 = 16

   x = 16-50

   x = -34

   __________________________

   h,x+13=32-56

   x + 13 =-24

   x = -24-13

   x = -37

   _________________________

   i,-15-x = (-14)-(-57)

   -15-x = -14 + 57

   -15-x =43

   x = -15-43

   x = -58

   __________________________

     j, I x-1 I = 5

   $\left[\begin{matrix} x+1=5\\ x-1=5\end{matrix}\right.$

   $\left[\begin{matrix} x=4\\ x=6\end{matrix}\right.$

   Vậy x= {4;6}

   color[pink][#Taki]

   Trả lời