helppppppppppppppppppppppppppppppppp
rút gọn
2 căn x – 9 /(căn x -3) * ( căn x -2 ) + 2 căn x +1 / căn x – 3 – căn x +3/ căn x -2
helppppppppppppppppppppppppppppppppp
rút gọn
2 căn x – 9 /(căn x -3) * ( căn x -2 ) + 2 căn x +1 / căn x – 3 – căn x +3/ căn x -2
Câu hỏi mới
Dkxd:x \ge 0;x \ne 4;x \ne 9\\
\dfrac{{2\sqrt x – 9}}{{\left( {\sqrt x – 3} \right).\left( {\sqrt x – 2} \right)}} + \dfrac{{2\sqrt x + 1}}{{\sqrt x – 3}} – \dfrac{{\sqrt x + 3}}{{\sqrt x – 2}}\\
= \dfrac{{2\sqrt x – 9 + \left( {2\sqrt x + 1} \right)\left( {\sqrt x – 2} \right) – \left( {\sqrt x + 3} \right).\left( {\sqrt x – 3} \right)}}{{\left( {\sqrt x – 3} \right).\left( {\sqrt x – 2} \right)}}\\
= \dfrac{{2\sqrt x – 9 + 2x – 4\sqrt x + \sqrt x – 2 – \left( {x – 9} \right)}}{{\left( {\sqrt x – 3} \right).\left( {\sqrt x – 2} \right)}}\\
= \dfrac{{2x – \sqrt x – 11 – x + 9}}{{\left( {\sqrt x – 3} \right).\left( {\sqrt x – 2} \right)}}\\
= \dfrac{{x – \sqrt x – 2}}{{\left( {\sqrt x – 3} \right).\left( {\sqrt x – 2} \right)}}\\
= \dfrac{{\left( {\sqrt x + 1} \right).\left( {\sqrt x – 2} \right)}}{{\left( {\sqrt x – 3} \right).\left( {\sqrt x – 2} \right)}}\\
= \dfrac{{\sqrt x + 1}}{{\sqrt x – 3}}
\end{array}$