Tính `A={4^3 .25^5 .9^4}/{8^2 .125^3 .3^7}` `B={6^3 +3. 6^2 +3^3}/13`

1 bình luận về “Tính `A={4^3 .25^5 .9^4}/{8^2 .125^3 .3^7}` `B={6^3 +3. 6^2 +3^3}/13`”

1. A=(4^3*25^5*9^4)/(8^2*125^3*3^7)

   =(2^6*5^10*3^8)/(2^6*5^9*3^7)

   =(5*3)/1

   =15

   $\\$

   B=(6^3 + 3 * 6^2 + 3^3)/13

   =(216+3*36+27)/13

   =(243+108)/13

   =351/13

   =27

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