31/23 – ( 7/32 + 8/23) (1/3+12/67+13/41) – (79/67 – 28/41)

2 bình luận về “31/23 – ( 7/32 + 8/23) (1/3+12/67+13/41) – (79/67 – 28/41)”

1. Giải đáp:

   31/23 – (7/32 + 8/23)

   = 31/23 – 7/32 – 8/23

   = (31/23-8/23) – 7/32

   = 1 – 7/32

   = 32/32 – 7/32

   = 25/32

   (1/3+12/67 + 13/41) – (79/67 – 28/41)

   = 1/3 + 12/67 + 13/41 – 79/67 + 28/41

   = 1/3 + (12/67 – 79/67) + (13/41 + 28/41)

   = 1/3 + (-1) + 1

   = 1/3 + (-1+1)

   = 1/3 + 0

   = 1/3

    

   Trả lời
2. 31/23 – ( 7/32 + 8/23)

   =31/23 –  7/32 – 8/23

   =(31/23 – 8/23) – 7/32

   =1 – 7/32

   =25/32

   (1/3+12/67+13/41) – (79/67 – 28/41)

   =1/3 + 12/67 + 13/41 – 79/67 – 28/41

   =(12/67 – 79/67) + (13/41 – 28/41) + 1/3

   =-1 + (-5/27) + 1/3

   =-32/27 + 1/3

   =-23/27

   Xin hay nhất

   Trả lời