a)3/5+1/5x=17/9 b)(-4/15-18/19)-(20/19+11/15) c)1- 1 1/7 + 8/11 + 8/15/0,875-1+7/11 +7/15 TÌm x a)1 1/5 + 4/5 :x =0,75 b)3 x

1 bình luận về “a)3/5+1/5x=17/9 b)(-4/15-18/19)-(20/19+11/15) c)1- 1 1/7 + 8/11 + 8/15/0,875-1+7/11 +7/15 TÌm x a)1 1/5 + 4/5 :x =0,75 b)3 x”

1. a,3/5+1/5x=17/9

   =>1/5x=17/9-3/5

   =>1/5x=58/45

   =>x=58/45:1/5

   =>x=58/9

   Vậy x=58/9

   $\\$

   b,(-4/15-18/19)-(20/19+11/15)

   =-4/15-18/19-20/19-11/15

   =(-4/15-11/15)-(18/19+20/19)

   =-1-2

   =-3

   $\\$

   c,(1-1 1/7+8/11+8/15)/(0,875-1+7/11+7/15)

   =(8/8-8/7+8/11+8/15)/(7/8-7/7+7/11+7/15)

   =(8(1/8-1/7+1/11+1/15))/(7(1/8-1/7+1/11+1/15))

   =8/7

   $\\$

   a,1 1/5+4/5:x=0,75

   =>4/5:x=0,75-1 1/5

   =>4/5:x=-9/20

   =>x=4/5:(-9)/20

   =>x=-16/9

   Vậy x=-16/9

   $\\$

   b,3*(5x+2/3)^2=4/3

   =>(5x+2/3)^2=4/3:3

   =>(5x+2/3)^2=4/9

   =>(5x+2/3)^2=(2/3)^2

   =>$\left[\begin{matrix} 5x+\dfrac{2}{3}=\dfrac{2}{3}\\ 5x+\dfrac{2}{3}=\dfrac{-2}{3}\end{matrix}\right.$

   =>$\left[\begin{matrix} 5x=0\\ 5x=\dfrac{-4}{3}\end{matrix}\right.$

   =>$\left[\begin{matrix} x=0\\ x=\dfrac{-4}{15}\end{matrix}\right.$

   Vậy x in{0;-4/15}

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