Trang chủ » Hỏi đáp » Môn Toán (1+1/2) x (1+1/3) x (1+1/4 ) x …….x (1+ 1/x) =1008 1/2 Tìm x cảm ưn ah 28/04/2023 (1+1/2) x (1+1/3) x (1+1/4 ) x …….x (1+ 1/x) =1008 1/2 Tìm x cảm ưn ah
(1+1/2) × (1+1/3) × (1+1/4 ) × …….× (1+ 1/x) =1008 1/2 3/2 × 4/3 × …… × x+1/x = 1008 1/2 \frac{3 × 4 × …. × ( x + 1 )}{2 × 3 × ….× x} = 1008 1/2 x + 1/2 = 2017/2 x + 1 = 2017 x = 2017 – 1 x = 2016 -> Vậy x = 2016 Trả lời
3/2xx4/3xx…..xx(x+1)/x=1008(1)/2 [3xx4xx…xx (x+1)]/[2xx3xx…xx x]=1008(1)/2 (x+1)/2=2017/2 =>x+1=2017 =>x=2016 Vậy x=2016 @lienlien55098 Trả lời
2 bình luận về “(1+1/2) x (1+1/3) x (1+1/4 ) x …….x (1+ 1/x) =1008 1/2 Tìm x cảm ưn ah”