Trang chủ » Hỏi đáp » Môn Toán 1/3+1/9+1/27+1/81+…+1/19683+1/59049 08/09/2024 1/3+1/9+1/27+1/81+…+1/19683+1/59049
Đặt: A=1/3+1/9+1/27+1/81+…+1/19683+1/59049 =1/3+1/3^2+1/3^3+1/3^4+…+1/3^9+1/3^10 3A=1+1/3+1/3^2+…+1/3^9 3A-A=(1+1/3+…+1/3^9)-(1/3+1/3^2+…+1/3^10) 2A=1-1/3^10 A=(1- 1/3^10)/2 *** $nhatminhbuithien2010$ Trả lời
Giải đáp: A=(3^10-1)/(2.3^10). Lời giải và giải thích chi tiết: Đặt A=1/3+1/9+1/27+1/81+……+1/19683+1/59059 A=1/3+1/3^2+1/3^3+1/3^4+…..+1/3^9+1/3^10 3A=1+1/3+1/3^2+1/3^3+……+1/3^8+1/3^9 3A-A=1+1/3+1/3^2+1/3^3+……+1/3^8+1/3^9-(1/3+1/3^2+1/3^3+1/3^4+…..+1/3^9+1/3^10) 2A=1-1/3^10 2A=(3^10-1)/3^10 A=(3^10-1)/(2.3^10). Trả lời
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