Tính a)`7- `1/7` b)`3/2` + 4 c)`8/3` – `4/5` d)`101/9` – 3 e)`8/7` x `14/24` f)`5/3` : `7/6` g)6 x `4/3` h)`18/7` : 2 i)`3/

1 bình luận về “Tính a)`7- `1/7` b)`3/2` + 4 c)`8/3` – `4/5` d)`101/9` – 3 e)`8/7` x `14/24` f)`5/3` : `7/6` g)6 x `4/3` h)`18/7` : 2 i)`3/”

1. a) $7-\frac{1}{7}=\frac{49}{7}-\frac{1}{7}=\frac{48}{7}=6\frac{6}{7}$ 

   b) $\frac{3}{2}+4=\frac{3}{2}+\frac{8}{2}=\frac{11}{2}=5\frac{1}{2}$

   c) $\frac{8}{3}-\frac{4}{5}=\frac{40}{15}-\frac{12}{15}=\frac{28}{15}=1\frac{13}{15}$ 

   d)$\frac{101}{9}-3=\frac{101}{9}-\frac{27}{9}=\frac{74}{9}=8\frac{2}{9}$

   e) $\frac{8}{7}\times \frac{14}{24}=\frac{8}{7}\times \frac{7}{12}=$ $\frac{8\times 7}{7\times 12}=\frac{8}{12}=\frac{2}{3}$

   f) $\frac{5}{3}÷\frac{7}{6}=\frac{5}{3}\times \frac{6}{7}=\frac{5\times 6}{3\times 7}=\frac{5\times 2}{7}=\frac{10}{7}=1\frac{3}{7}$

   g) $6\times \frac{4}{3}=\frac{6\times 4}{3}=2\times 4=8$

   h) $\frac{18}{7}÷2=\frac{18}{7}\times \frac{1}{2}=\frac{18}{7\times 2}=\frac{9}{7}=1\frac{2}{7}$ 

   i) $\frac{3}{2}+\frac{4}{5}+\frac{7}{10}=\frac{15}{10}+\frac{8}{10}+\frac{7}{10}=\frac{30}{10}=3$

   j) $7-(\frac{4}{3}+\frac{5}{6})=7-(\frac{8}{6}+\frac{5}{6})=7-\frac{13}{6}=\frac{42}{6}-\frac{13}{6}=\frac{29}{6}=4\frac{5}{6}$

   k) $\frac{3}{2}\times \frac{4}{5}\times \frac{7}{9}=\frac{3\times 4\times 7}{2\times 5\times 9}=\frac{2\times 7}{5\times 3}=\frac{14}{15}$

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