12 chia hết (x +3)

1 bình luận về “12 chia hết (x +3)”

1. 12 vdots (x+3)

   => x+3 in Ư(12)

   => x+3 in {±1;±2;±3;±4;±6;±12}

   Ta có bảng sau:

   \begin{array}{|c|c|c|}\hline \text{x+3}&\text{-1}&\text{1}&\text{-2}&\text{2}&\text{-3}&\text{3}&\text{-4}&\text{4}&\text{-6}&\text{6}&\text{-12}&\text{12}\\\hline \text{x}&\text{-4}&\text{-2}&\text{-5}&\text{-1}&\text{-6}&\text{0}&\text{-7}&\text{1}&\text{-9}&\text{3}&\text{-15}&\text{9}\\\hline\end{array}

   Vậy …

   ————

   6 vdots x-1

   => x-1 in Ư(6)

   => x-1 in {±1;±2;±3;±6}

   Ta có bảng sau:

   \begin{array}{|c|c|c|}\hline \text{x-1}&\text{-1}&\text{1}&\text{-2}&\text{2}&\text{-3}&\text{3}&\text{-6}&\text{6}\\\hline \text{x}&\text{0}&\text{2}&\text{-1}&\text{3}&\text{-2}&\text{4}&\text{-5}&\text{7}\\\hline\end{array}

   Vậy …

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