Môn Toán A = 1+1/2+(1/2)^2 + ( 1/2)^3 + ( 1/2)^4 + ( 1/2)^5 +…..+ ( 1/2)^2021 chứng minh a = 2- (1/2) ^2021 16 Tháng Năm, 2023 2 Comments A = 1+1/2+(1/2)^2 + ( 1/2)^3 + ( 1/2)^4 + ( 1/2)^5 +…..+ ( 1/2)^2021 chứng minh a = 2- (1/2) ^2021
A = 1 + 1/2 + ( 1/2 )^2 + ( 1/2 )^3 + … + ( 1/2 )^{2021} => 2A = 2 + 1 + 1/2 + ( 1/2 )^2 + … + ( 1/2 )^{2020} => 2A – A = ( 2 + 1 + 1/2 + ( 1/2 )^2 + … + ( 1/2 )^{2020} ) – ( 1 + 1/2 + ( 1/2 )^2 + ( 1/2 )^3 + … + ( 1/2 )^{2021} ) => A = 3 – 1 – ( 1/2 )^{2021} => A = 2 – ( 1/2 )^{2021} Vậy : A = 2 – ( 1/2 )^{2021} Trả lời
2A=2+1+1/2+(1/2)^2+…+(1/2)^2020 2A-A=2+1+1/2+(1/2)^2+…+(1/2)^2020-1-1/2-(1/2)^2-…-(1/2)^2021 A=2-(1/2)^2021 (đpcm) @lienlien55098 Trả lời
2 bình luận về “A = 1+1/2+(1/2)^2 + ( 1/2)^3 + ( 1/2)^4 + ( 1/2)^5 +…..+ ( 1/2)^2021 chứng minh a = 2- (1/2) ^2021”