a)2 mũ 3+3 mũ 2
b) 2 mũ 2 ×18-2 mũ 3 ×8
c) 90÷[39-(8-5)mũ 2]
d)4×5 mũ 2-2 mũ 3×(3 mũ 2 +2020mũ 0)
e)820-{40×[120-70):25+2mũ 3]
g)2mũ x+12=44
a)2 mũ 3+3 mũ 2
b) 2 mũ 2 ×18-2 mũ 3 ×8
c) 90÷[39-(8-5)mũ 2]
d)4×5 mũ 2-2 mũ 3×(3 mũ 2 +2020mũ 0)
e)820-{40×[120-70):25+2mũ 3]
g)2mũ x+12=44
Câu hỏi mới
a)17\\
b)8\\
c)3\\
d)20\\
e)420\\
g)x = 5
\end{array}$
a){2^3} + {3^2}\\
= 8 + 9\\
= 17\\
b){2^2}.18 – {2^3}.8\\
= 4.18 – 8.8\\
= 72 – 64\\
= 8\\
c)90:\left[ {39 – {{\left( {8 – 5} \right)}^2}} \right]\\
= 90:\left( {39 – {3^2}} \right)\\
= 90:\left( {39 – 9} \right)\\
= 90:30\\
= 3\\
d){4.5^2} – {2^3}.\left( {{3^2} + {{2020}^0}} \right)\\
= 4.25 – 8.\left( {9 + 1} \right)\\
= 100 – 8.10\\
= 100 – 80\\
= 20\\
e)820 – \left\{ {40.\left[ {\left( {120 – 70} \right):25 + {2^3}} \right]} \right\}\\
= 820 – 40.\left( {50:25 + 8} \right)\\
= 820 – 40.\left( {2 + 8} \right)\\
= 820 – 40.10\\
= 820 – 400\\
= 420\\
g){2^x} + 12 = 44\\
\Leftrightarrow {2^x} = 44 – 12\\
\Leftrightarrow {2^x} = 32\\
\Leftrightarrow {2^x} = {2^5}\\
\Leftrightarrow x = 5\\
Vậy\,x = 5
\end{array}$