D)(-40)+(-13)+40+(-13) E)5-(4-7+12)+(4-7+12) F)(-5)+(-15)+8+(-8)

2 bình luận về “D)(-40)+(-13)+40+(-13) E)5-(4-7+12)+(4-7+12) F)(-5)+(-15)+8+(-8)”

1. D) (-40)+(-13)+40+(-13)

   = [ (-40+40 ] +[ ( -13 )+( -13 )

   = 0+( -26 )

   = 0 – 26

   = -26

   —————————————-

   E) 5-(4-7+12)+(4-7+12)

   = 5 – 4+7 – 12+4 – 7+12

   = 5 – ( 4 – 4 )+( 7 – 7 ) – ( 12 – 12 )

   = 5 – 0+0 – 0

   = 5

   —————————————-

   F) (-5)+(-15)+8+(-8)

   = [ ( -5 )+( -15 ) ]+[ 8+( -8 ) ]

   = -20+0

   = – 20 

   —————————————–

   @Avocado

    

   Trả lời
2. d)

   (-40) + (-13) + 40 + (-13)

   = [(-40) + 40] + [(-13) + (-13)]

   = 0 + (-26)

   = 0 – 26

   = -26

   e)

   5 – (4-7+12) + (4-7+12)

   = 5 – 4+7-12 + 4-7+12

   = 5 – (4-4) + (7-7) – (12-12)

   = 5-0+0-0

   = 5

   f)

   (-5) + (-15) + 8 + (-8)

   = [(-5) + (-15)] + [8+(-8)]

   = (-20) + 0

   = -20

   #BadMo od

    

   Trả lời