Tìm x. Biết (x 2/3 )³ = 1/27 (x + 1/2 ) ² = 1/6 60% x + 2/3x = 76

Tìm x. Biết

(x 2/3 )³ = 1/27

(x + 1/2 ) ² = 1/6

60% x + 2/3x = 76

2 bình luận về “Tìm x. Biết (x 2/3 )³ = 1/27 (x + 1/2 ) ² = 1/6 60% x + 2/3x = 76”

  1. #Aridoto
    a,(x-2/3)^3=1/27
    ↔(x-2/3)^3=(1/3)^3
    ↔x-2/3=1/3
    ↔x=1/3+2/3
    ↔x=1
    b,(x+1/2)^2=1/6
    ↔(x+1/2)^2=(\sqrt{6}/6)^2
    TH1:
    x+1/2=\sqrt{6}/6
    ↔x=\sqrt{6}/6-1/2
    ↔x=-7/12
    TH2:
    x+1/2=(-\sqrt{6})/6
    ↔x=(-\sqrt{6})/6-1/2
    ↔x=(-3-\sqrt{6})/6
    c,60%x+2/3x=76
    ↔3/5x+2/3x=76
    ↔19/15x=76
    ↔x=76:19/15
    ↔x=60

    Trả lời
  2. ( x – $\frac{2}{3}$ ) ³ = $\frac{1}{27}$ 
    ⇒ ( x – $\frac{2}{3}$ ) ³ = ( $\frac{1}{3}$  ) ³
    ⇒ x – $\frac{2}{3}$ = $\frac{1}{3}$ 
    ⇒ x = 1
    _________________________________________________
    ( x + $\frac{1}{2}$ ) ² = $\frac{1}{6}$ 
    ⇒ x² + $\frac{1}{4}$ = $\frac{1}{6}$ 
    ⇒ x² = $\frac{1}{12}$
    ⇒ x =  $\sqrt{\frac{1}{12}}$
    _________________________________________________
    60% x + $\frac{2}{3}$ x = – 76
    ⇒ x  ( $\frac{3}{5}$ + $\frac{2}{3}$ ) = – 76
    ⇒ x $\frac{19}{15}$ = – 76
    ⇒ x = -76$\frac{15}{19}$
     

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