(-1/2x^2-x) (6x+3)-(3x-1) (x^2+1/2)+1/2( x + 4)

1 bình luận về “(-1/2x^2-x) (6x+3)-(3x-1) (x^2+1/2)+1/2( x + 4)”

1. (-1/2x^2-x) (6x+3)-(3x-1) (x^2+1/2)+1/2( x + 4)

   = -1/2 x^2 . 6x – 1/2 x ^2 . 3 – x . 6x – x.3 – (3x. x^2 + 3x . 1/2 – x^2 – 1/2) + 1/2  . x + 1/2 . 4

   = -3x^3 – 3/2 x^2 -6x^2 – 3x – (3x^3+3/2x -x^2 -1/2)+ 1/2 x +2

   = -3x^3 – 3/2x^2 – 6x^2 – 3x – 3x^3 – 3/2x + x^2 + 1/2 + 1/2x + 2

   = (-3x^3 – 3x^3) + (-3/2 x^2 -6x^2 + x^2) + (-3x-3/2x +1/2x) + (1/2+2)

   = -6x^3 -13/2x^2 -4x +5/2

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