$(x+2{)}^{n+11}$ = $(x+2{)}^{n+11}$

2 bình luận về “$(x+2{)}^{n+11}$ = $(x+2{)}^{n+11}$”

1. Giải đáp+Lời giải và giải thích chi tiết:

   (x+2)^{n+1} = (x+2)^{n+11}

   hay: (x+2)^{n+11}=(x+2)^{n+1}

   =>(x+2)^{n+11}-(x+2)^{n+1}=0

   =>(x+2)^{n+1}[(x+2)^{10}-1]=0

   => $[\begin{array}{l}(x+2{)}^{n+1}=0\\ (x+2{)}^{10}-1=0\end{array}$ 

   => $[\begin{array}{l}x+2=0\\ (x+2{)}^{10}=1\end{array}$ 

   => $[\begin{array}{l}x=-2\\ x+2=-1\\ x+2=1\end{array}$ 

   => $[\begin{array}{l}x=-2\\ x=-3\\ x=-1\end{array}$ 

   Vậy x in {-3;-2;-1}

   #Eudo ria

   Trả lời
2. (x+2)^(n+1) = (x+2)^(n+11)

   -> (x+2)^(n+1) – (x+2)^(n+11) = 0

   -> (x+2)^(n+1)*1-(x+2)^(n+1)*(x+2)^10 = 0

   -> (x+2)^(n+1)[1-(x+2)^10] = 0

   TH1:

   (x+2)^(n+1) = 0

   -> x + 2 = 0

   -> x = 0 – 2

   -> x = -2

   TH2:

   1-(x+2)^10=0

   -> (x+2)^10=1-0

   -> (x+2)^10=1

   -> [((x+2)^10=1^10),((x+2)^10=(-1)^10):}

   -> [(x+2=1),(x+2=-1):}

   -> [(x=1-2),(x=-1-2):}

   -> [(x=-1),(x=-3):}

   Vậy x = -2,x=-1,x=-3

   Trả lời