Trang chủ » Hỏi đáp » Môn Toán A] 7+[7/12 – 1/2 +3]-[1/12+5] B]1-{1:[2^3 +1-(-1/2^2)]} 27/12/2024 A] 7+[7/12 – 1/2 +3]-[1/12+5] B]1-{1:[2^3 +1-(-1/2^2)]}
a) 7+(7/12 – 1/2 + 3)-(1/12+5) =7+(7/12 – 6/12 + 36/12)-(1/12+60/12) =7+37/12 – 61/12 = 84/12 +37/12 -61/12 =5 b) 1-{1:[2^3 +1-(-1/2^2)]} =1−[1:(8+1+1/4)] =1-[1:(32/4+4/4+1/4)] =1−(1:37/4) =1−4/37 =33/37 Trả lời
a) 7 + (7/12 – 1/2 + 3) – (1/12 + 5) = 7 + (7/12 – 6/12 + 36/12) – (1/12 + 60/12) = 7 + 37/12 – 61/12 = 84/12 + 37/12 – 61/12 = 60/12 = 5 ———— b) 1 – {1 : [2^3 + 1 – (- 1/2^2)]} = 1 – [1 : (8 + 1 + 1/4)] = 1 – [1 : (32/4 + 4/4 + 1/4)] = 1 – (1 : 37/4) = 1 – 4/37 = 33/37 $# ????????????????????$ Trả lời
2 bình luận về “A] 7+[7/12 – 1/2 +3]-[1/12+5] B]1-{1:[2^3 +1-(-1/2^2)]}”