Cho đa thức : `P ( x ) = x5 - 3 x 2 x 4- 1 /2 x - x 5 5 x 4 x 2 - 1 ` `Q ( x ) = x - x 9 x 2 - 5x 3 x 6

Question

Cho đa thức :  `P ( x ) = x^5 - 3 x ^2 + x ^4-  1 /2 x - x ^5 + 5 x ^4 + x ^2 - 1 ` `Q ( x ) = x - x ^9 + x ^2 - 5x ^3 + x^ 6 - x + 3 x^ 9 + 2 x ^6 - x ^3 + 7`  Tính : `Q(x) - P(x)`

truongthanhhung · Answer

P(x)=x^5-3x^2+x^4-1/2x-x^5+5x^4+x^2-1   =(x^5-x^5)+(x^4+5x^4)+(-3x^2+x^2)-1/2x-1   =6x^4-2x^2-1/2x-1   Q(x)=x-x^9+x^2-5x^3+x^6-x+3x^9+2x^6-x^3+7   =(-x^9+3x^9)+(x^6+2x^6)+(-5x^3-x^3)+x^2+(x-x)+7   =2x^9+3x^6-6x^3+x^2+7   Ta c&oacute;:   Q(x)-P(x)   =2x^9+3x^6-6x^3+x^2+7-(6x^4-2x^2-1/2x-1)   =2x^9+3x^6-6x^3+x^2+7-6x^4+2x^2+1/2x+1   =2x^9+3x^6-6x^4-6x^3+3x^2+1/x+8   Vậy Q(x)-P(x)=2x^9+3x^6-6x^4-6x^3+3x^2+1/2x+8

tuyen98 · Answer

th&ocirc;ng cảm m&aacute;y chụp hơi xấu  :-(

Cho đa thức : `P ( x ) = x^5 – 3 x ^2 + x ^4- 1 /2 x – x ^5 + 5 x ^4 + x ^2 – 1 ` `Q ( x ) = x – x ^9 + x ^2 – 5x ^3 + x^ 6

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