d) `x:(2/9-1/5)=8/16 e) `1/3+1/2:x=1/5` g) `|x+1|=3`

1 bình luận về “d) `x:(2/9-1/5)=8/16 e) `1/3+1/2:x=1/5` g) `|x+1|=3`”

1. Giải đáp:

    d)

   x:(\frac{2}{9}-\frac{1}{5})=\frac{8}{16}

   => x:(\frac{10}{45}-\frac{9}{45})=\frac{1}{2}

   => x:\frac{1}{45}=\frac{1}{2}

   => x=\frac{1}{2}.\frac{1}{45}

   =>x=\frac{1}{90}

   Vậy x=\frac{1}{90}

   e)

   \frac{1}{3}+\frac{1}{2}:x=\frac{1}{5}

   => \frac{1}{2}:x=\frac{1}{5}-\frac{1}{3}

   => \frac{1}{2}:x=\frac{3}{15}-\frac{5}{15}

   => \frac{1}{2}:x=\frac{-2}{15}

   => x=\frac{1}{2}:(-\frac{2}{15})

   => x=-\frac{15}{4}

   Vậy x=-\frac{15}{4}

   g)

   |x+1|=3

   Ta xét 2TH:

   +)TH1: x+1=3

   => x=3-1

   =>x=2

   +)TH2: x+1=-3

   => x=-3-1

   => x=-4

   Vậy x\in{2;-4}

   #\mathcal{DN}

    

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