(x-5)(x-1)=(x-1)(x-2)

2 bình luận về “(x-5)(x-1)=(x-1)(x-2)”

1. Giải đáp:

   (x-5).(x-1)=(x-1).(x-2)

   =>(x-5).(x-1)-(x-1).(x-2)=0

   =>(x-1).[(x-5)-(x-2)]=0

   =>(x-1).(x-5-x+2)=0

   =>(x-1).(-3)=0

   =>x-1=0

   =>x=1

   Vậy x=1

   Trả lời
2. (x-5)(x-1)=(x-1)(x-2)

   <=>(x-5)(x-1)-(x-1)(x-2)=0

   <=>x^2-x-5x+5-(x^2-2x-x+2)=0

   <=>x^2-x-5x+5-x^2+2x+x-2=0

   <=>-3x+3=0

   <=>-3(x-1)=0

   <=>x-1=0

   <=>x=1

   Vậy x=1

    

   Trả lời