Bài 2 Cho m= 3x²-7x³+5x-9 n=6x³-7x-5x²+16 Tính theo hàng dọc a,M+N b,M-N c,N

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1. a) M + N:

   (3x² – 7x³ + 5x – 9)

   • (6x³ – 7x – 5x² + 16)

   -7x³ – 5x² + 9x + 7

   Vậy M + N = -7x³ – 5x² + 9x + 7.

   b) M – N:

   (3x² – 7x³ + 5x – 9)

   • (6x³ – 7x – 5x² + 16)

   7x³ + 5x² – 1x – 25

   Vậy M – N = 7x³ + 5x² – x – 25.

   c) N – M:

   (6x³ – 7x – 5x² + 16)

   • (3x² – 7x³ + 5x – 9)

   7x³ + 5x² – 1x + 25

   Vậy N – M = 7x³ + 5x² – x + 25.

    

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