tính A=(16/3-2^2×5/3)×(17/3-2^5×5/3)×…×(30/3-2^2×5/3)

1 bình luận về “tính A=(16/3-2^2×5/3)×(17/3-2^5×5/3)×…×(30/3-2^2×5/3)”

1. Giải đáp: $A=0$

    

   Lời giải và giải thích chi tiết:

   $A=\left( \dfrac{16}{3}-\dfrac{{{2}^{2}}.5}{3} \right)\left( \dfrac{17}{3}-\dfrac{{{2}^{2}}.5}{3} \right)…\left( \dfrac{30}{3}-\dfrac{{{2}^{2}}.5}{3} \right)$

   $A=\left( \dfrac{16}{3}-\dfrac{20}{3} \right)\left( \dfrac{17}{3}-\dfrac{20}{3} \right)…\left( \dfrac{30}{3}-\dfrac{20}{3} \right)$

   $A=\left( \dfrac{16}{3}-\dfrac{20}{3} \right)\left( \dfrac{17}{3}-\dfrac{20}{3} \right)…\left( \dfrac{20}{3}-\dfrac{20}{3} \right)…\left( \dfrac{30}{3}-\dfrac{20}{3} \right)$

   $A=\left( \dfrac{16}{3}-\dfrac{20}{3} \right)\left( \dfrac{17}{3}-\dfrac{20}{3} \right)…0…\left( \dfrac{30}{3}-\dfrac{20}{3} \right)$

   $A=0$

   Trả lời