Trang chủ » Hỏi đáp » Môn Toán Tìm x: a)3/7+2|3/4+1/5x|=|-4/3| 17/09/2024 Tìm x: a)3/7+2|3/4+1/5x|=|-4/3|
Giải đáp: 3/7+2|3/4+1/5x|=|-4/3| => 3/7+2|3/4+1/5x|=4/3 => 2|3/4+1/5x|=4/3-3/7 => 2|3/4+1/5x|=19/21 => |3/4+1/5x|=19/21:2 => |3/4+1/5x|=19/42 TH1: 3/4+1/5x=19/42 => 1/5x=19/42-3/4 => 1/5x=-25/84 => x=-25/84 : 1/5 => x=-125/84 TH2: 3/4+1/5x=-19/42 => 1/5x=-19/42-3/4 => 1/5x=-101/84 => x=-101/84:1/5 => x=-505/84 Vậy x∈{-125/84; -505/84} Trả lời
Giải đáp+Lời giải và giải thích chi tiết: 3/7+2|3/4+1/5x|=|-4/3| =>2|3/4+1/5x|=4/3-3/7 =>|3/4+1/5x|=19/21:2 =>|3/4+1/5x|=19/42 <=>\(\left[ \begin{array}{l}\dfrac{3}{4}+\dfrac{1}{5}x= \dfrac{19}{42} \\\dfrac{3}{4}+\dfrac{1}{5}x= -\dfrac{19}{42}\end{array} \right.\) <=>\(\left[ \begin{array}{l}\dfrac{1}{5}x= \dfrac{19}{42}-\dfrac{3}{4} \\\dfrac{1}{5}x= -\dfrac{19}{42}-\dfrac{3}{4}\end{array} \right.\) <=>\(\left[ \begin{array}{l}\dfrac{1}{5}x= -\dfrac{25}{84} \\\dfrac{1}{5}x= -\dfrac{101}{84}\end{array} \right.\) <=>\(\left[ \begin{array}{l}x= -\dfrac{125}{84} \\x= -\dfrac{505}{84}\end{array} \right.\) Vậy \(\left[ \begin{array}{l}x= -\dfrac{125}{84} \\x= -\dfrac{505}{84}\end{array} \right.\) Trả lời
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