Tìm x: a)3/7+2|3/4+1/5x|=|-4/3|

Tìm x:
a)3/7+2|3/4+1/5x|=|-4/3|

2 bình luận về “Tìm x: a)3/7+2|3/4+1/5x|=|-4/3|”

  1. Giải đáp:
    3/7+2|3/4+1/5x|=|-4/3|
    => 3/7+2|3/4+1/5x|=4/3
    => 2|3/4+1/5x|=4/3-3/7
    => 2|3/4+1/5x|=19/21
    => |3/4+1/5x|=19/21:2
    => |3/4+1/5x|=19/42
    TH1:
    3/4+1/5x=19/42
    => 1/5x=19/42-3/4
    => 1/5x=-25/84
    => x=-25/84 : 1/5
    => x=-125/84
    TH2:
    3/4+1/5x=-19/42
    => 1/5x=-19/42-3/4
    => 1/5x=-101/84
    => x=-101/84:1/5
    => x=-505/84
    Vậy x∈{-125/84; -505/84}

    Trả lời
  2. Giải đáp+Lời giải và giải thích chi tiết:
    3/7+2|3/4+1/5x|=|-4/3| 
    =>2|3/4+1/5x|=4/3-3/7 
    =>|3/4+1/5x|=19/21:2 
    =>|3/4+1/5x|=19/42
    <=>\(\left[ \begin{array}{l}\dfrac{3}{4}+\dfrac{1}{5}x= \dfrac{19}{42} \\\dfrac{3}{4}+\dfrac{1}{5}x= -\dfrac{19}{42}\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}\dfrac{1}{5}x= \dfrac{19}{42}-\dfrac{3}{4} \\\dfrac{1}{5}x= -\dfrac{19}{42}-\dfrac{3}{4}\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}\dfrac{1}{5}x= -\dfrac{25}{84} \\\dfrac{1}{5}x= -\dfrac{101}{84}\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x= -\dfrac{125}{84} \\x= -\dfrac{505}{84}\end{array} \right.\)
    Vậy \(\left[ \begin{array}{l}x= -\dfrac{125}{84} \\x= -\dfrac{505}{84}\end{array} \right.\)

    Trả lời

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