tính A +(-2/3) ^2 .2023 + (-4/9).2022 +(3/2)^2 TÌM X 2x=3/2x+25% tìm x n |x-4|-|x+1|+-1 mong mn giúp

1 bình luận về “tính A +(-2/3) ^2 .2023 + (-4/9).2022 +(3/2)^2 TÌM X 2x=3/2x+25% tìm x n |x-4|-|x+1|+-1 mong mn giúp”

1. Giải đáp:

   $\begin{array}{l}
   A = {\left( { – \dfrac{2}{3}} \right)^2}.2023 + \left( { – \dfrac{4}{9}} \right).2022 + {\left( {\dfrac{3}{2}} \right)^2}\\
    = \dfrac{4}{9}.2023 – \dfrac{4}{9}.2022 + \dfrac{9}{4}\\
    = \dfrac{4}{9}.\left( {2023 – 2022} \right) + \dfrac{9}{4}\\
    = \dfrac{4}{9}.1 + \dfrac{9}{4}\\
    = \dfrac{4}{9} + \dfrac{9}{4}\\
    = \dfrac{{97}}{{36}}\\
   b)\\
   2x = \dfrac{3}{2}.x + 25\% \\
    \Leftrightarrow 2x – \dfrac{3}{2}.x = \dfrac{{25}}{{100}}\\
    \Leftrightarrow \left( {2 – \dfrac{3}{2}} \right).x = \dfrac{1}{4}\\
    \Leftrightarrow \dfrac{1}{2}.x = \dfrac{1}{4}\\
    \Leftrightarrow x = \dfrac{1}{4}:\dfrac{1}{2}\\
    \Leftrightarrow x = \dfrac{1}{2}\\
   \end{array}$

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