Tính nhanh vậy có thể: `d) 4/9 . 23/11 – 1/11 . 4/9 + 4/9` ` e) 1/7 . (-3/8) + -13/18 . 1/7` `g) (1/117` `-` `4/123)` `- (118

2 bình luận về “Tính nhanh vậy có thể: `d) 4/9 . 23/11 – 1/11 . 4/9 + 4/9` ` e) 1/7 . (-3/8) + -13/18 . 1/7` `g) (1/117` `-` `4/123)` `- (118”

1. $\text{d) $\frac{4}{9}$.$\frac{23}{11}$ – $\frac{1}{11}$.$\frac{4}{9}$ + $\frac{4}{9}$  }$

   $\text{= $\frac{4}{9}$.($\frac{23}{11}$ – $\frac{1}{11}$ + 1)  }$

   $\text{= $\frac{4}{9}$.($\frac{22}{11}$  + 1)  }$

   $\text{= $\frac{4}{9}$.(2  + 1)  }$

   $\text{= $\frac{4}{9}$.3  }$

   $\text{= $\frac{12}{9}$  }$

   $\text{= $\frac{4}{3}$  }$

   —————————————————

   $\text{e) $\frac{1}{7}$.(-$\frac{13}{18}$) + – $\frac{13}{18}$.$\frac{1}{7}$ }$

   $\text{= $\frac{1}{7}$.(-$\frac{3}{8}$ – $\frac{13}{18})$)  }$

   $\text{= $\frac{1}{7}$.(-$\frac{79}{72}$)  }$

   $\text{=- $\frac{79}{504}$ }$

   ——————————————————–

   $\text{ g) ($\frac{1}{117}$ – $\frac{4}{123}$) – ($\frac{118}{117}$ – $\frac{1}{2}$ + $\frac{119}{123}$) }$

   $\text{= $\frac{1}{117}$ – $\frac{4}{123}$ – $\frac{118}{117}$ + $\frac{1}{2}$ – $\frac{119}{123}$  }$

   $\text{=  ($\frac{1}{117}$ – $\frac{118}{117}$) – ($\frac{4}{123}$ + $\frac{119}{123}$) + $\frac{1}{2}$}$

   $\text{=  -$\frac{117}{117}$ – $\frac{123}{123}$ + $\frac{1}{2}$}$

   $\text{=  -1 – 1 + $\frac{1}{2}$}$

   $\text{=  -2 + $\frac{1}{2}$}$

   $\text{=  -$\frac{3}{2}$}$

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   Trả lời
2. Giải đáp:

   d) 4/9 . 23/11 – 1/11 . 4/9 + 4/9

   = 4/9 . (23/11 – 1/11 + 1)

   = 4/9 . (22/11 + 1)

   = 4/9 . (2+1)

   = 4/9 . 3

   = 4/3

   e) 1/7 . (-3/8) + (-13/18) . 1/7

   = 1/7 . (-3/8 – 13/18)

   = 1/7 . (-79/72)

   = -79/504

   g) (1/117 – 4/123) – (118/117 – 1/2 + 119/123)

   = 1/117 – 4/123 – 118/117 + 1/2 – 119/123

   = (1/117 – 118/117) + (-4/123 – 119/123) + 1/2

   = -1 + (-1) + 1/2

   = -2 + 1/2

   = -3/2

    

   Trả lời