`1 ) ( 1 - x ² ) ³` `2) 1/64 a ³` `3) 8z ³ - 125` `4) 8x ³ 12x ² 6x 1 ` `5) 1 - 9x 27x ² - 27x ³` `6) ( x 3y ) (

Question

`1 ) ( 1 - x ² ) ³` `2) 1/64 + a ³` `3) 8z ³ - 125` `4) 8x  ³ + 12x ² + 6x + 1 ` `5) 1 - 9x + 27x ² - 27x ³` `6) ( x + 3y ) ( x ² - 3xy + 9y ² )` `7) ( 2a - b ) ( 4a ² + 2ab + b ²)`

kimnguenoanh · Answer

1)   (1-x^2)^3   =1^3-3.1^(2).x+3.1.x^2-(x^2)^3   =1-3x+3x^2-x^6   2) 1/64+a^3   =(1/4)^3+a^3   =(1/4+a).[(1/4)^2-1/(4).a+a^2]   =(1/4+a).(1/16-1/4a+a^2)   3)    8z^3-125   =(2z)^3-5^3   =(2z-5).[(2z)^2+2z.5+5^2]   =(2z-5).(4z^2+10x+25)   4)   8x^3+12x^2+6x+1   =(2x)^3+3.(2x)^(2).1+3.2x.1^2+1^3   =(2x+1)^3   5)   1-9x+27x^2-27x^3   =1^3-3.1^(2).3x+3.1.(3x)^(2)-(3x)^3   =(1-3x)^3   6) (x+3y).(x^2-3xy+9y^2)   =(x+3y).[x^2-x.3y+(3y)^2]   =x^3+(3y)^3   =x^3+27y^3   7)   (2a-b).(4a^2+2ab+b^2)   =(2a-b).[(2a)^2+2a.b+b^2]   =(2a)^3-b^3   =8a^3-b^3

`1 ) ( 1 – x ² ) ³` `2) 1/64 + a ³` `3) 8z ³ – 125` `4) 8x ³ + 12x ² + 6x + 1 ` `5) 1 – 9x + 27x ² – 27x ³` `6) ( x + 3y ) (

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