1/2x-5 + 1/2x+5 – 6x-5/4x^2-25 1/3x-2 – 1/3x+2 + 3x-6/9x^2-4

1/2x-5 + 1/2x+5 – 6x-5/4x^2-25
1/3x-2 – 1/3x+2 + 3x-6/9x^2-4

2 bình luận về “1/2x-5 + 1/2x+5 – 6x-5/4x^2-25 1/3x-2 – 1/3x+2 + 3x-6/9x^2-4”

  1. a)
    1/(2x – 5) + 1/(2x + 5) – (6x – 5)/(4x^2 – 25)
    = 1/(2x – 5) + 1/(2x + 5) – (6x – 5)/((2x – 5)(2x + 5)) [MTC: (2x – 5)(2x + 5)]
    = (2x + 5)/((2x – 5)(2x + 5)) + (2x – 5)/((2x + 5)(2x – 5)) – (6x – 5)/((2x – 5)(2x + 5))
    = (2x + 5 + 2x – 5 – 6x + 5)/((2x – 5)(2x + 5))
    = (-2x + 5)/((2x – 5)(2x + 5))
    = (5 – 2x)/((2x – 5)(2x + 5))
    b)
    1/(3x + 2) – 1/(3x – 1) + (3x – 6)/(9x^2 – 4)
    = 1/(3x + 2) – 1/(3x – 2) + (3x – 6)/[(3x – 2)(3x + 2)] [MTC: (3x – 2)(3x + 2)]
    = (3x – 2)/[(3x + 2)(3x – 2)] – (3x + 2)/[(3x – 2)(3x + 2)] + (3x – 6)/[(3x – 2)(3x + 2)]
    = (3x – 2 – 3x – 2 + 3x – 6)/[(3x + 1)(3x – 1)]
    = (3x – 2)/[(3x + 2)(3x – 2)]
    = 1/(3x + 2)

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