Trang chủ » Hỏi đáp » Môn Toán x/x-1 + 3/x+1 – x^2+1/x^2-1 x-2/x^2-2x+1 . (x-1)^3/2 14/08/2024 x/x-1 + 3/x+1 – x^2+1/x^2-1 x-2/x^2-2x+1 . (x-1)^3/2
x/(x-1)+3/(x+1)-(x^2+1)/(x^2-1)(ĐKne1; x\ne-1) =x/(x-1)+3/(x+1)-(x^2+1)/((x-1).(x+1)) =(x.(x+1)+3.(x-1)-(x^2+1))/((x-1).(x+1)) =(x^2+x+3x-3-x^2-1)/((x-1).(x+1)) =(4x-4)/((x-1).(x+1)) =(4.(x-1))/((x-1).(x+1)) =4/(x-1) $\\$ (x-2)/(x^2-2x+1).((x-1)^3)/2(ĐK:x\ne1) =(x-2)/((x-1)^2).((x-1)^3)/(2) =(x-2).(x-1)/2 =((x-2).(x-1))/2 Trả lời
1 bình luận về “x/x-1 + 3/x+1 – x^2+1/x^2-1 x-2/x^2-2x+1 . (x-1)^3/2”