Trang chủ » Hỏi đáp » Môn Toán 1/x(x+y) + 1/y(x+y) 2x^2-xy/x-y + xy+y^2/y-x + 2y^2-x^2/x-y 10/08/2024 1/x(x+y) + 1/y(x+y) 2x^2-xy/x-y + xy+y^2/y-x + 2y^2-x^2/x-y
Giải đáp: \frac{1}{x.(x+y)}+\frac{1}{y.(x+y)} (x\ne0;y\ne0;x\ney;x\ne-y) =\frac{1.y}{xy.(x+y)}+\frac{1.x}{xy(x+y)} =\frac{y+x}{xy.(x+y)} =\frac{x+y}{xy.(x+y)} =\frac{1}{xy} ______________________ \frac{2x^{2}-xy}{x-y}+\frac{xy+y^{2}}{y-x}+\frac{2y^{2}-x^{2}}{x-y} (x\ney) =\frac{2x^{2}-xy}{x-y}-\frac{xy+y^{2}}{x-y}+\frac{2y^{2}-x^{2}}{x-y} =\frac{2x^{2}-xy-xy-y^{2}+2y^{2}-x^{2}}{x-y} =\frac{x^{2}-2xy+y^{2}}{x-y} =\frac{(x-y)^{2}}{x-y} =x-y Trả lời
1 bình luận về “1/x(x+y) + 1/y(x+y) 2x^2-xy/x-y + xy+y^2/y-x + 2y^2-x^2/x-y”