2(3x-1)=4x-10 (x+3)(3x-1)=0 8+x/6-1/8=x/12

2 bình luận về “2(3x-1)=4x-10 (x+3)(3x-1)=0 8+x/6-1/8=x/12”

1. a)

   2(3x-1)=4x-10

   <=>6x-2=4x-10

   <=>6x-4x=(-10)-(-2)

   <=>2x=-8

   <=>x  =-8:2

   <=>x  =-4

   toVậy S={-4}

   b)

   (x+3)(3x-1)=0

   <=>x+3=0 hoặc 3x-1=0

   <=>x    =-3         3x   =1

   <=>                       x     =1/3

   toVậy S={-3;1/3}

   c)

   (8+x)/6-1/8=x/12

   <=>[8(8+x)]/48-6/48=4x/48

   =>8(8+x)-6=4x

   <=>64+8x-6=4x

   <=>8x-4x=6-64

   <=>4x     =-58

   <=>x       =-58:4

   <=>x       =-29/2

   toVậy S={-29/2}

   —

   8 + x/6 – 1/8 = x/12
   <=> 8 + x/6 – 1/8 – x/12 = 0
   <=> x/12 + 63/8 = 0
   <=> x/12 = -63/8

   <=>x  =(-63.12)/8

   <=> x = -189/2
   toVậy S = {-189/2}

    

   Trả lời
2. 2(3x-1) = 4x -10

   <=> 6x – 2 – 4x + 10 = 0

   <=> 2x + 8 = 0

   <=> 2x = -8

   <=> x = -4

   Vậy x = -4

   —–

   (x+3)(3x-1)=0

   TH1 

   x + 3 = 0

   <=> x = -3

   TH2 

   3x – 1 = 0

   <=> 3x = 1

   <=> x = 1/3

   Vậy x = -3;x=1/3

   —–

   8 + x/6 – 1/8 = x/12

   <=> 8 + x/6 – 1/8 – x/12 = 0

   <=> x/12 + 63/8 = 0

   <=> x/12 = -63/8

   <=> x = -189/2

   Vậy x = -189/2

   —–

   #lynlyn

    

   Trả lời