x/(x – 2) + (5x – 4)/3x ^ 2 – 6x – 2/3x 3x+3/4x+2 + x+5/x+2 Giúp mình vs

2 bình luận về “x/(x – 2) + (5x – 4)/3x ^ 2 – 6x – 2/3x 3x+3/4x+2 + x+5/x+2 Giúp mình vs”

1. x/(x-2)+(5x-4)/(3x^2-6x)-2/(3x)

   =x/(x-2)+(5x-4)/(3x(x-2))-2/(3x)

   =(x*3x+5x-4-2*(x-2))/(3x(x-2))

   =(3x^2+5x-4-2x+4)/(3x(x-2))

   =(3x^2+3x)/(3x(x-2))

   =(3x(x+1))/(3x(x-2))

   =(x+1)/(x-2)

   (3x+3)/(4x+2)+(x+5)/(x+2)

   =(3x+3)/(2(2x+1))+(x+5)/(x+2)

   =((3x+3)*(x+2)+(x+5)*2*(2x+1))/(2(2x+1)(x+2)

   =(3x^2+9x+6+4x^2+22x+10)/(2(2x+1)(x+2)

   =(7x^2+31x+16)/(4x^2+10x+4)

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   Trả lời
2. $\frac{x}{(x-2)}$+ $\frac{5x-4}{3x^2-6x}$-$\frac{2}{3x}$= $\frac{x}{x-2}$+ $\frac{5x}{3x(x-2)}$- $\frac{2}{3x}$

   = $\frac{x.3x}{3x(x-2)}$+ $\frac{5x-4}{3x(x-2)}$- $\frac{2(x-2)}{3x(x-2)}$

   = $\frac{3x^2}{3x(x-2)}$+ $\frac{5x-4}{3x(x-2)}$- $\frac{2x-4}{3x(x-2)}$

   = $\frac{3x^2+3x}{3x(x-2)}$

   = $\frac{3x(x+1)}{3x(x-2)}$= $\frac{x+1}{x-2}$

   $\frac{3x+3}{4x+2}$+ $\frac{x+5}{x+2}$

   =$\frac{3x+3}{2(2x+1)}$+ $\frac{x+5}{x+2}$

   = $\frac{3x^2+9x+6}{2(2x+1)(x+2)}$+ $\frac{4x^2+22x+10}{2(2x+1)(x+2)}$

   = $\frac{7x^2+31x+16}{4x^2+10x+4}$ 

   Trả lời