Trang chủ » Hỏi đáp » Môn Toán (2020-x)3 +(2022-x)3 + (2x-4042)2=0 15/07/2023 (2020-x)3 +(2022-x)3 + (2x-4042)2=0
( 2020 – x ) . 3 + ( 2022 – x ) . 3 + ( 2x – 4042 ) . 2 = 0 TH1 : ( 2020 – x ) . 3 = 0 ⇔ 2020 – x = 0 ⇔ x = 2020 TH2 : ( 2022 – x ) . 3 = 0 ⇔ 2022 – x = 0 ⇔ x = 2022 TH3 : ( 2x – 4042 ) . 2 = 0 ⇔ 2x – 4042 = 0 ⇔ 2x = 4042 ⇔ x = 2021 Vậy S = { 2020 ; 2022 ; 2021 } Trả lời
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