4x^2 – 4x + 1 x^3 – 27 x^3 – 4x^2 + 3x 4x^2 – 12x + 3

1 bình luận về “4x^2 – 4x + 1 x^3 – 27 x^3 – 4x^2 + 3x 4x^2 – 12x + 3”

1. 4x^2 – 4x + 1

   = (2x)^2 – 2.2x.1 + 1^2

   = (2x-1)^2

   x^3 – 27

   = x^3 – 3^3

   = (x-3)(x^2 + 3x + 9)

    x^3 – 4x^2 + 3x

   = x(x^2 – 4x + 3)

   = x(x^2 – x – 3x + 3)

   = x[x(x-1) – 3(x-1)]

   = x(x-1)(x-3)

   4x^2 – 12x + 3

   = 4x^2 – 12x + 9 – 6

   = (2x – 3)^2 – (\sqrt[6])^2

   = (2x-3 – \sqrt[6])(2x – 3 + \sqrt[6])

    

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