4x/4x^2-9 + 1/2x+3 – 1/2x-3 1/x+3 – 1/x-3 + 2x/x^2-9

2 bình luận về “4x/4x^2-9 + 1/2x+3 – 1/2x-3 1/x+3 – 1/x-3 + 2x/x^2-9”

1. (4x)/(4x^2-9) + 1/(2x+3) – 1/(2x-3)

   =(4x)/((2x-3)(2x+3)) + 1/(2x+3) – 1/(2x-3)

   =(4x+(2x-3)-(2x+3))/((2x+3)(2x-3))

   =(4x-6)/((2x+3)(2x-3))

   =(2(2x-3))/((2x+3)(2x-3))

   =2/(2x+3)

   1/(x+3) – 1/(x-3) + (2x)/(x^2-9)

   =1/(x+3) – 1/(x-3) + (2x)/((x-3)(x+3)

   =((x-3)-(x+3)+2x)/((x-3)(x+3)

   =(x-3-x-3+2x)/((x-3)(x+3)

   =(2x-6)/((x-3)(x+3)

   =(2(x-3))/((x-3)(x+3)

   =2/(x+3)

   Bạn có thể tham khảo!

   Trả lời
2. (4x)/(4x^2-9)+1/(2x+3)-1/(2x-3)(ĐK:x\ne+-3/2)

   =(4x+(2x-3)-(2x+3))/((2x+3).(2x-3))

   =(4x+2x-3-2x-3)/((2x+3).(2x-3))

   =(4x-6)/((2x+3).(2x-3))

   =(2.(2x-3))/((2x+3).(2x-3))

   =2/(2x+3)

   $\\$

   1/(x+3)-1/(x-3)+(2x)/(x^2-9)(ĐK:x\ne+-3)

   =((x-3)-(x+3)+2x)/((x-3).(x+3))

   =(x-3-x-3+2x)/((x-3).(x+3))

   =(2x-6)/((x-3).(x+3))

   =(2.(x-3))/((x-3).(x+3))

   =2/(x+3)

   Trả lời