Trang chủ » Hỏi đáp » Môn Toán `x^{5}-2018x^{4}+2016x^{3}+2018x^{2}-2016x-2017` `PTĐT TNT` 20/09/2024 `x^{5}-2018x^{4}+2016x^{3}+2018x^{2}-2016x-2017` `PTĐT TNT`
x^5-2018x^4+2016x^3+2018x^2-2016x-2017 =x^5-2017x^4-x^4+2017x^3-x^3+2017x^2+x^2-2017x+x-2017 =(x^5-2017x^4)-(x^4-2017x^3)-(x^3-2017x^2)+(x^2-2017x)+(x-2017) =x^4(x-2017)-x^3(x-2017)-x^2(x-2017)+x(x-2017)+(x-2017) =(x-2017)(x^4-x^3-x^2+x+1) Trả lời
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