`a) 5x - 7 = 23` `b) 2 - ( 3x - 7 )/4 ( x 17 )/5 = 0` `c) 4x 5 = 3(x2) 4` `d) ( x - 1 )( x 2 ) = 0`

Question

`a) 5x - 7 = 23` `b) 2 - ( 3x - 7 )/4 + ( x + 17 )/5 = 0` `c) 4x + 5 = 3(x+2) + 4` `d) ( x - 1 )( x + 2 ) = 0`

lanngocha · Answer

a) 5x - 7 = 23 <=>5x = 30 <=>x = 6 Vậy S={6} b, 2 - (3x-7)/4 + (x+17)/5 = 0 <=>40/20 - (15x+35)/20 + (4x+68)/20 = 0 <=>40 - 15x + 35 + 4x + 68 = 0 <=>-11x+143=0 <=>-11x=-143 <=>x=13 Vậy S={13} c,4x+5 = 3(x+2) + 4 <=>4x+5 = 3x + 6 + 4 <=>4x-3x = 10 - 5 <=>x = 5 Vậy S={5} d,(x-1)(x+2) = 0 <=>(x-1) = 0 hoặc (x+2) = 0 <=>x= 1 hoặc x = -2 Vậy S={1;-2}

mocmien87 · Answer

a,5x-7 = 23 <=>5x = 30 <=>x = 6 Vậy S={6} b, 2 - (3x-7)/4 + (x+17)/5 = 0 <=>40/20 - (5(3x-7))/20 + (4(x+17))/20 = 0 <=>40 - 15x + 35 + 4x + 68 = 0 <=>-15x + 4x = 0 -40 - 35 - 68 <=>-11x = -143 <=>x = 13 Vậy S={13} c,4x+5 = 3(x+2) + 4 <=>4x+5 = 3x + 6 + 4 <=>4x-3x = 10 - 5 <=>x = 5 Vậy S={5} d,(x-1)(x+2) = 0 <=>x-1=0 hoặc x+2=0 <=>x=1 hoặc x=-2 Vậy S={1;-2}

`a) 5x – 7 = 23` `b) 2 – ( 3x – 7 )/4 + ( x + 17 )/5 = 0` `c) 4x + 5 = 3(x+2) + 4` `d) ( x – 1 )( x + 2 ) = 0`

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