#wdr x^3-2x^2+2x-1=0 (x^3-1)-(2x^2-2x)=0 (x-1)(x^2+x+1) – 2x(x-1)=0 (x-1)(x^2+x+1-2x)=0 => x-1=0 x=1 => x^2+x+1-2x=0 (x+1)^2 +x=0 (x+1)^2 =-x => x={∅} Vậy x={1} Trả lời
1 bình luận về “x³-2x²+2x-1=0 tìm x ạ!!”