a) (12x ^ 4 * y ^ 3 + 8x ^ 3 * y ^ 2 – 4x * y ^ 2) / 2 * xy b) (6x ^ 2 + 17x + 12) / (2x + 3) c) (x ^ 3 + x

1 bình luận về “a) (12x ^ 4 * y ^ 3 + 8x ^ 3 * y ^ 2 – 4x * y ^ 2) / 2 * xy b) (6x ^ 2 + 17x + 12) / (2x + 3) c) (x ^ 3 + x”

1. Giải đáp:$\begin{array}{l}
   a)6{x^3}{y^2} + 4{x^2}y – 2y\\
   b)3x + 4\\
   c){x^2} – x
   \end{array}$

    

   Lời giải và giải thích chi tiết:

   $\begin{array}{l}
   a)\dfrac{{12{x^4}{y^3} + 8{x^3}{y^2} – 4x{y^2}}}{{2xy}}\\
    = \dfrac{{2xy.\left( {6{x^3}{y^2} + 4{x^2}y – 2y} \right)}}{{2xy}}\\
    = 6{x^3}{y^2} + 4{x^2}y – 2y\\
   b)\dfrac{{\left( {6{x^2} + 17x + 12} \right)}}{{2x + 3}}\\
    = \dfrac{{6{x^2} + 9x + 8x + 12}}{{2x + 3}}\\
    = \dfrac{{3x.\left( {2x + 3} \right) + 4\left( {2x + 3} \right)}}{{2x + 3}}\\
    = \dfrac{{\left( {2x + 3} \right)\left( {3x + 4} \right)}}{{2x + 3}}\\
    = 3x + 4\\
   c)\dfrac{{{x^3} + {x^2} – 2x}}{{x + 2}}\\
    = \dfrac{{{x^3} + 2{x^2} – {x^2} – 2x}}{{x + 2}}\\
    = \dfrac{{{x^2}\left( {x + 2} \right) – x\left( {x + 2} \right)}}{{x + 2}}\\
    = \dfrac{{\left( {x + 2} \right)\left( {{x^2} – x} \right)}}{{x + 2}}\\
    = {x^2} – x
   \end{array}$ 

   Trả lời