Phân tích thành nhân tử: a, 3x³- 8x² -41x+ 30 b, 16x(x-y)-x+y c,16x³-54x³ Helpp mình zới

29/02/2024

2 bình luận về “Phân tích thành nhân tử: a, 3x³- 8x² -41x+ 30 b, 16x(x-y)-x+y c,16x³-54x³ Helpp mình zới</p”

1. a) 3x^3- 8x^2 – 41x + 30

   = 3x^3 + 7x^2− 15x^2 – 6x − 35x + 30

   = 3x^3 + 7x^2− 6x – 15x^2 − 35x + 30

   = x (3x^2 + 7x− 6) – 5 (3x^2 − 7x + 6)

   = (x – 5) (3x^2 + 7x− 6)

   = (x – 5) (3x^2 + 9x – 2x − 6)

   = (x – 5) [3x (x + 3) – 2 (x − 3)]

   = (x – 5) (3x – 2) (x + 3)

   b) 16x (x – y) – x + y

   = 16x (x – y) – (x – y)

   = (16x – 1) (x – y)

   c) 16x^3 – 54x^3

   = -38x^3

   $\textit{#TranDucQuangNBK}$

   Trả lời
2. a, 3x^3-8x^2-41x+30

   =3x^3-15x^2+7x^2-35x-6x+30

   =3x^2(x-5)+7x(x-5)-6(x-5)

   =(x-5)(3x^2+7x-6)

   =(x-5)(3x^2+9x-2x-6)

   =(x-5)[3x(x+3)-2(x+3)]

   =(x-5)(x+3)(3x-2)

   b, 16x(x-y)-x+y

   =16x(x-y)-1*(x-y)

   =(x-y)(16x-1)

   c, 16x^3-54x^3

   =-38x^3

   Trả lời