Trang chủ » Hỏi đáp » Môn Toán th phép tính a, `6x(2x+3) -(3x-1)(4x+1)` b, `(16x^5y^6 – 12x^3y^4 – 6x^3y^2) : 4x^2y^2` 31/10/2024 th phép tính a, `6x(2x+3) -(3x-1)(4x+1)` b, `(16x^5y^6 – 12x^3y^4 – 6x^3y^2) : 4x^2y^2`
a) 6x(2x+3) – (3x-1)(4x+1) = 12x^2 + 18x – (3x.4x + 3x.1 – 1.4x – 1.1) = 12x^2 + 18x – (12x^2 + 3x – 4x – 1) = 12x^2 + 18x – 12x^2 – 3x + 4x + 1 = (12x^2 – 12x^2) + (18x – 3x+4x) + 1 = 19x+1 b) (16x^5y^6 – 12x^3y^4 – 6x^3y^2) : 4x^2y^2 = 16x^5y^6 : 4x^2y^2 – 12x^3y^4 : 4x^2y^2 – 6x^3y^2 : 4x^2y^2 = 4x^3y^4 – 3xy^2 – 3/2x #FFVN Trả lời
2 bình luận về “th phép tính a, `6x(2x+3) -(3x-1)(4x+1)` b, `(16x^5y^6 – 12x^3y^4 – 6x^3y^2) : 4x^2y^2`”